What is the capacity of a 4-inch pipe that is 18 inches long?

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Multiple Choice

What is the capacity of a 4-inch pipe that is 18 inches long?

Explanation:
To determine the capacity of a 4-inch pipe that is 18 inches long, it is essential to first calculate the volume of the pipe, which is shaped like a cylinder. The formula for the volume (V) of a cylinder is given by: \[ V = \pi r^2 h \] Where: - \( r \) is the radius, - \( h \) is the height (or length of the cylinder), - \( \pi \) is approximately 3.14159. For a 4-inch diameter pipe, the radius \( r \) can be calculated as half of the diameter: \[ r = \frac{4 \, \text{inches}}{2} = 2 \, \text{inches} \] The height \( h \) is given as 18 inches. Now, substituting these values into the volume formula: \[ V = \pi (2 \, \text{inches})^2 (18 \, \text{inches}) \] \[ V = \pi (4 \, \text{square inches})(18 \, \text{inches}) \] \[ V = \pi (72 \, \text{cubic inches

To determine the capacity of a 4-inch pipe that is 18 inches long, it is essential to first calculate the volume of the pipe, which is shaped like a cylinder. The formula for the volume (V) of a cylinder is given by:

[ V = \pi r^2 h ]

Where:

  • ( r ) is the radius,

  • ( h ) is the height (or length of the cylinder),

  • ( \pi ) is approximately 3.14159.

For a 4-inch diameter pipe, the radius ( r ) can be calculated as half of the diameter:

[ r = \frac{4 , \text{inches}}{2} = 2 , \text{inches} ]

The height ( h ) is given as 18 inches. Now, substituting these values into the volume formula:

[ V = \pi (2 , \text{inches})^2 (18 , \text{inches}) ]

[ V = \pi (4 , \text{square inches})(18 , \text{inches}) ]

[ V = \pi (72 , \text{cubic inches

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